Question

The sum of the additive inverse and multiplicative inverse of 3/4 is

Answer 1

$Given\: number = \frac{3}{4}$

$\blue { Additive \: inverse \:of \:the \: number = \frac{ -3}{4}}$

$\pink { Multiplicative \: inverse \:of \:the \: number = \frac{ 4}{3}}$

/* According to the problem given */

$Sum \:of \: the \: additive \: inverse \: and \\multiplicative \: inverse \:of \:\frac{3}{4} \\= \frac{-3}{4} + \frac{4}{3} \\= \frac{-9+16}{12} \\= \frac{7}{12}$

Therefore.,

$\red{ Required \:sum } \green {= \frac{7}{12}}$

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