The sum of the age of father and hos son is 72 years. After 2 years father will be 4 uears less than 3 times the age of son . Find presnt ages
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let the present age of son is x
and age of father is 72-x
then after 2 years
according to question
(72-x)+2 = 3(x+2)-4
72-x = 3x+6-4-2
72 - x = 3x+6-6
72-x = 3x
3x+x = 72
4x = 72
x = 72/4
x = 18
the present age of son is 18 years
the present age of father is 72-18 = 54
and age of father is 72-x
then after 2 years
according to question
(72-x)+2 = 3(x+2)-4
72-x = 3x+6-4-2
72 - x = 3x+6-6
72-x = 3x
3x+x = 72
4x = 72
x = 72/4
x = 18
the present age of son is 18 years
the present age of father is 72-18 = 54
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