The sum of the age of father and the son is 48 year . the quotient obtained by dividing the age of son by the age of father is 1/ 5 .find their ages.
Answers
Answered by
22
fathers age = x
Son age = 48 - x
(48 - x) / x = 1/5
240 - 5x = x
6x = 240
x = 40
fathers age = 40 yrs
son age = 48 - x = 48 - 40 = 8 yrs
Thanks
Son age = 48 - x
(48 - x) / x = 1/5
240 - 5x = x
6x = 240
x = 40
fathers age = 40 yrs
son age = 48 - x = 48 - 40 = 8 yrs
Thanks
Answered by
44
Hi ,
Let the age of the father = x years
age of son = ( 48 - x ) years
according to the problem given ,
( 48 - x ) / x = 1/5
5( 48 - x ) = x
240 - 5x = x
240 = 6x
x = 240/6
x = 40
Therefore ,
age of the father = x = 40 years
age of the son = 48 - x
= 48 - 40
= 8 years
I hope this helps you.
: )
Let the age of the father = x years
age of son = ( 48 - x ) years
according to the problem given ,
( 48 - x ) / x = 1/5
5( 48 - x ) = x
240 - 5x = x
240 = 6x
x = 240/6
x = 40
Therefore ,
age of the father = x = 40 years
age of the son = 48 - x
= 48 - 40
= 8 years
I hope this helps you.
: )
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