Math, asked by samiksha010429, 10 days ago

the sum of the age of mother and daughter is 103. mother is elder than daughter by 47 year. find their present age​

Answers

Answered by Anonymous
367

Answer:

\Large\mathcal{\red{Answer}}

\implies Daughter's age is 28 years.

\implies Mother's present age is 75 years.

Step-by-step explanation:

\underline\mathtt{\red{Heya! \ Let's \ do \ it!!}}

Given, Sum of age of mother and daughter is 103 respectively.

  • Mother is elder than daughter by 47 years.

To find:-

\implies Their respective present age.

Let the present age of the daughter be x.

\therefore Present age of the mother is (x+47) years.

Also,

Given that the sum of the ages of mother and daughter is 103.

\implies x + x + 47 = 103

\implies 2x = 103 - 47

\implies 2x = 56

\implies x = \frac{56}{2}

\implies x = 28

Hence, daughter's age is 28 years.

& Her mother's age = x + 47 years

\implies Mother's age is 28+47 = 75 years.

Answered by Anonymous
250

\Large\mathcal{\green{Answer}}

⟹ Daughter's age is 28 years.

⟹ Mother's present age is 75 years.

Step-by-step explanation:

\underline\mathtt{\red{Heya! \ Let's \ do \ it!!}}

Given,

Sum of age of mother and daughter is 103 respectively.

Mother is elder than daughter by 47 years.

To find:-

⟹ Their respective present age.

Let the present age of the daughter be x.

∴ Present age of the mother is (x+47) years.

Also,

Given that the sum of the ages of mother and daughter is 103.

⟹ x + x + 47 = 103

⟹ 2x = 103 - 47

⟹ 2x = 56

⟹ x = \frac{56}{2}

⟹ x = 28

Hence, daughter's age is 28 years.

& Her mother's age = x + 47 years

⟹ Mother's age is 28+47 = 75 years.

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