The sum of the age of two sister is 38. The younger sister was 4 years younger than older ten years ago. How old is the younger
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Given:
The sum of the age of two sister is 38. The younger sister was 4 years younger than older ten years ago.
To Find:
How old is the younger?
Solution:
Present age
Let age of younger sister = X years
Age of older sister = 38 - X
Past age
Before 10 years, age of younger and older sister was:
Age of younger sister = X - 10
Age of older sister = 38 - X - 10 = 28 - X
From given question:
The younger sister was 4 years younger than older ten years ago:
X-10 = 28 - X - 4
X- 10 = 24 - X
X + X = 24 + 10
2X = 34
Means:
X = 17 years
Present age of younger sister is 17 years.
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