Question

The sum of the ages of 2 brothers is 50. Ten years ago the elder brother had twice the age of the younger . What is the present age of the elder

Answer 1

age of younger brother = x

age of elder brother = 50 -x

Ten years ago

younger brother = x - 10

elder brother = 50 - x - 10   or  2(x-10)

40 - x = 2x - 20

3x =60

x = 20

Present age of elder brother = 50 - 20 = 30 years