Question

the sum of the ages of 3 person is 150years.10 years ago their ages were in the ratio 7:8:9 their present age is

Answer 1

Solution :-

Given :
The sum of the ages of 3 persons is 150 years.

10 years ago,
Ratio of their ages 7 : 8 : 9

Let the present ages of 3 persons be (7x + 10), (8x + 10) and (9x + 10).


According to the question,


$= > (7x + 10) + (8x + 10) + (9x + 10) = 150 \\ \\ = > 7x + 10 + 8x + 10 + 9x + 10 = 150 \\ \\ = > 24x + 30 = 150 \\ \\ = > 24x = 150 - 30 \\ \\ = > 24x = 120 \\ \\ = > x = \frac{120}{24} = 5$



Therefore,
Present age of 1st person = (7x + 10) = (7 × 5) + 10 = 45 years
Present age of 2nd person = (8x + 10) = (8 × 5) + 10 = 50 years
Present age of 3rd person = (9x + 10) = (9 × 5) + 10 = 55 years

Answer 2

HELLO GUYS

QUESTIONS :)

the sum of the ages of 3 person is 150years.10 years ago their ages were in the ratio 7:8:9 their present age is

ANSWER :)

Given

SUM of 3 person age =150

10 year ago

The sum of person age =120 ( age of every single person increases or decreases with same rate)

10 year back sum of there age =150-30=120

Ratio of there age = 7:8:9

Sum of ratio =7+8+9=24

Value of 1 ratio =120/24=5

So age of first person was=7x5=35

Age of 2nd person was =8x5=40

Age age of 3rd person was =9x5=45

The present age of 1st=35+10=45yr

2nd=40+10=50yr

3rd=45+10=55

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