Question

The sum of the ages of 3persons is150years.10years ago their ages were in the ratio 7:8:9

Answer 1

Solutions :-

Given :
The sum of the ages of three persons = 150 years.
10 years ago, their ages were in the ratio 7: 8 : 9.

Let the present ages of three persons be 7x + 10, 8x + 10 and 9x + 10 respectively.


According to the question,

=> 7x + 10 + 8x + 10 + 9x + 10 = 150
=> 24x + 30 = 150
=> 24x = 150 - 30
=> 24x = 120
=> x = 120/24 = 5

Therefore,
7x + 10 = (7 × 5) + 10 = 45
8x + 10 = (8 × 5) + 10 = 50
9x + 10 = (9 × 5) + 10 = 55


Hence,
The present ages of three persons are 45 years , 50 years and 55 years respectively.

Answer 2

$\underline{\underline{\Huge\mathfrak{Answer ;}}}$

Dear ,

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-: Step by Step Explanation ;-
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Given ;-
• Three person's age sum = 150 years.

• About 10 years before , their ages were as in the ratio = 7:8:9 respectively.

Now ,
Assuming their present ages as ;-
• 7y + 10
• 8y + 10
• 9y + 10

Then ,
According to the Question ;-

$= > 7y + 10 + 8y + 10 + 9y + 10$
$= > 24y + 30 = 150$
$= > 24y = 150 - 30$
$= > 24y = 120$
$= > y = \frac{120}{24} = 5$

Now ,

$7y + 10 = 7 \times 5 + 10 = 45 \: years$
$8y + 10 = 8 \times 5 + 10 = 50 \: years$
$9y + 10 = 9 \times 5 + 10 = 55 \: years$

Therefore ,
45 years , 50 years and 55 years are the present ages of the three person's respectively.

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