Question

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child ?

A) 4 B) 8 C) 10 D) None

Answer 1

Let the age of the youngest child be x years.

Every child was born after an interval of 3 years.

Age of the four elder siblings = (x+3) years , (x+6) years, (x+9) years, (x+12) years

According to the question,

x+x+3+x+6+x+9+x+12=50

=>5x+30=50

=>5(x+6)=5×10

=>x+6=10

=>x=10-6=4

Thus, age of the youngest child

= x years = A. 4 years

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Answer 2

Answer:

Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.

According to Question now,

➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

➳ 5x + 30 = 50

➳ 5x = 50 - 30

➳ x = 20/5

➳ x = 4 years

Hence,the age of youngest child is 4 years.