Question

The sum of the ages of a and b is 37 year
five years ago, A's age was twice that of
b
Find their present age ​

Answer 1

Answer:

A=23; B=14

Step-by-step explanation:

Let A's present age be x years.

Let B's present age be y years.

x + y = 37

y=37-x ------------------------ (1)

5 years ago,

A's age= x-5

B's age= y-5

According to question,

(x-5)=2(y-5)

Substituting value of y from (1),

(x-5)=2(37-x-5)

x-5=2(32-x)

x-5=64-2x

3x=64+5

3x=69

x=69/3

x=23 years

y= 37-x=37-23

y=14 years

Answer 2

Step-by-step explanation:

Since we are talking about 5 years ago their present age will be (a+5) and (b+5) respectively.

As per the question,

a=2b (1)

(a-5)+ (b-5) =37 (2)

putting the value of a in eq (2)

(2b-5)+(b-5) = 37

3b-10 = 37

b = 27/3 = 9

therefore a = 2b= 2×9 = 18 (from eq1)

therefore their present ages are (a+5) = 18+5=23

and b+5 = 9+5 = 14