The sum of the ages of A and B is 46. Five years ago, the age of B was twice that of A. Find A's age
Answers
Answered by
8
Step-by-step explanation:
The sum of the ages of A and B is 46. Five years ago , the age of B was twice that of A. Find A's age.
5 years ago::
Let A's age be x
Age of B = 2x - 5 yrs
A. T. Q. :-
2x - 5 + x= 46
3x - 5 = 46
3x = 46+5
x = 51/3
x = 17
∴ A is 17 years old.
Answered by
4
Answer
17
Step-by-step explanation:
A/C to que.
A+B=46 -(1)
5 years ago, their age would be
A-5 & B-5
Therefore, B-5 = 2(A-5)
B-5 = 2A-10
B=2A-5
Now,
A+2A-5=46
3A-5=46
3A=51
A=51/3
A=17
HOPE THIS HELPED.
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