Question

The sum of the ages of A and B is 46. Five years ago, the age of B was twice that of A. Find A's age​

Answer 1

Step-by-step explanation:

The sum of the ages of A and B is 46. Five years ago , the age of B was twice that of A. Find A's age.

5 years ago::

Let A's age be x

Age of B = 2x - 5 yrs

A. T. Q. :-

2x - 5 + x= 46

3x - 5 = 46

3x = 46+5

x = 51/3

x = 17

∴ A is 17 years old.

Answer 2

Answer

17

Step-by-step explanation:

A/C to que.

A+B=46     -(1)

5 years ago, their age would be

A-5 & B-5

Therefore, B-5 = 2(A-5)

B-5 = 2A-10

B=2A-5

Now,

A+2A-5=46

3A-5=46

3A=51

A=51/3

A=17

HOPE THIS HELPED.