The sum of the ages of A and B is 46 years. five years ago the age of B was twice that of A. Find A age.
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Answer:
let the age of A be x years
and the age of B be 46-x years
A/Q,
46-x-5=2(x-5)
41-x=2x-10
-x-2x=-10-41
-3x=-51
x=17
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