The sum of the ages of A and B is 60 years
and 10 years hence A will be three times as
old as B. Find their present ages
(a) 65,20
o 50, 10
(C) 60, 20 (d) 70,20
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Answer:
let the present ages of A and B be x , y respectively .
x + y = 60. (1)
according to second condition
(x+10) = 3(y+10)
x+10 = 3y + 30
x - 3y = 20. (2)
multiplying eq (1) by 3
3x + 3y = 180. (3)
adding eq (2) & (3)
x - 3y = 20
+ 3x + 3y = 180
4x = 200
x = 50
substituting value of x in eq (1)
x + y = 60
50 + y = 60
y =10
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