Question

The sum of the ages of a, b, and c at present is 85 years. 10 years ago the ratio of their ages was 1:3: 7. The present age of c is what percentage age of b?55.55% 80% 120% 180% 300%

Answer 1

Answer:

the age before 10years

85-30=55

1x+3x+7x=55

11x=55

x=55/11

x=5

age of a= 1x=1*x=1*5=5

age of b=3x=3*x=3*5=15

age of c =7x=7*x=7*5=35

the present age

age of a =5+10=15

age of b=15+10=25

age of c=35+10=45

the percentage of c

45/25*100

$c \div b \times 100$

180 percent