the sum of the ages of a boy and his brother is 12 years and the sum of the square of their ages is 74 in years find their ages
Answers
Answered by
65
let the age of younger boy=x
so, the age of his brother= 12-x
Given,x²+(12-x)²=74
=x²+x²-24x+144=74
=2x²-24x+144-74=0
=2x²-24x+70=0
=x²-12x+35=0
=x²-5x-7x+35=0
=x(x-5)-7(x-5)=0
=(x-7)(x-5)=0
so,x will be 5 because he is younger.
so,age of the younger brother is 5 And of elder brother is 7.
Hope, you will like the answer
so, the age of his brother= 12-x
Given,x²+(12-x)²=74
=x²+x²-24x+144=74
=2x²-24x+144-74=0
=2x²-24x+70=0
=x²-12x+35=0
=x²-5x-7x+35=0
=x(x-5)-7(x-5)=0
=(x-7)(x-5)=0
so,x will be 5 because he is younger.
so,age of the younger brother is 5 And of elder brother is 7.
Hope, you will like the answer
Answered by
0
Answer:
Step-by-step explanation:
So X+Y=12 so the ages are x and x+12 once you square and add them it should be 74 according to the given condition in the question :
x^2+(12-x)^2=74
after doing some basic algebra you will get x=5 and x=7
Both values are correct since they havent specified which is older or younger.
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