Question

the sum of the ages of a boy and his father is 132 and the ratio of their ages in 7:4, how much older is the father then the son ?


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Answer 1

Answer:

Father is older than his son by 36 years

Step-by-step explanation:

Given :

Ratio of the ages = 7 : 4

Sum of their ages = 132

To find :

How much older is the father than the son

Solution :

Let their ages be -

• Father as 7y
• Son as 4y

⇒ 7y + 4y = 132

⇒ 11y = 132

⇒ y = 132/11

⇒ y = 12

★ Value of 7y

⇒ 7(12)

⇒ 84

Father is 84 years old

$\rule{300}{1.5}$

★ Value of 4y

⇒ 4(12)

⇒ 48

Son is 48 years old

$\rule{300}{1.5}$

$\textsf{\underline{\underline{Difference between their ages =}}}$

⇒ 84 - 48

⇒ 36

Father is older than his son by 36 years.

$\therefore$ Father is older than his son by 36 years.

Answer 2

Answer:

the ratio of age between the son and father = 7:4

let the age of the son and the father be 4x and 7x respectively.

=> 4x + 7x = 132

    11x = 132

    x = 132/11

    x = 12

therefore, the age of the son = 4x = 4(12) = 48

                  and, the age of the father = 7x = 7(12) = 84

therefore the father is 36 years older than the son.