the sum of the Ages of a boy is elder brother is the 12 years and the sum of square of the square of their ages in 74 find their ages
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Let the age of younger boy=x
so, the age of his brother= 12-x
Given,x²+(12-x)²=74
=x²+x²-24x+144=74
=2x²-24x+144-74=0
=2x²-24x+70=0
=x²-12x+35=0
=x²-5x-7x+35=0
=x(x-5)-7(x-5)=0
=(x-7)(x-5)=0
so,x will be 5 because he is younger.
so,age of the younger brother is 5 And of elder brother is 7.
_________________________
HOPE , IT HELPS ...✌️
________________________
________________________
Let the age of younger boy=x
so, the age of his brother= 12-x
Given,x²+(12-x)²=74
=x²+x²-24x+144=74
=2x²-24x+144-74=0
=2x²-24x+70=0
=x²-12x+35=0
=x²-5x-7x+35=0
=x(x-5)-7(x-5)=0
=(x-7)(x-5)=0
so,x will be 5 because he is younger.
so,age of the younger brother is 5 And of elder brother is 7.
_________________________
HOPE , IT HELPS ...✌️
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