Question

The sum of the ages of a father and his
son is 45 years. Three years ago, the
product of their ages (in years) was 74
years. Determine the present age of the
son.​

Answer 1

Answer:

son is 9

Step-by-step explanation:

the present age of the son will be (45−x) years.

Five years ago, the age of father was (x−5) years and that of son was (45−x−5)=(40−x) years.

As, five years ago, the product of ages was 124.

(x−5)(40−x)=124

⇒x

2

−45x+324=0

⇒(x−9)(x−36)=0

⇒x=9,x=36

When x=36, the age of father is 36 and the age of son is 9 years.

When x=36, the age of the father is 9 years and the age of the son is 36 years, which cannot be possible, so the present age of father is 36 years and that of the son is 9 years