The sum of the ages of a father and his son is 45 years. Five years ago the product of the their ages (in years) was 124. Determine their present ages.
Answers
Answered by
1
Answer:
36 years and 9 years
Step-by-step explanation:
Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.
Similar questions