Question

The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 34. The ages of the son and the father are respectively

Answer 1

hope it will help you

Answer 2

Answer:

• 39 years - Father's age.
• 6 years - Son's age.

Step-by-step explanation:

Given

• The sum of the ages of a father and his son is 45 years.
• Five years ago, the product of their ages was 34.

To find

• Present ages of son and the father.

Solution

Let the present age of the father be x years.

Then, son's present age will be 45 - x years.

Father's age 5 years ago = x - 5 years.

Son's age 5 years ago = 45 - x - 5 = 40 - x years.

Product of their ages = 34

(x - 5) (40 - x) = 34

• x² - 45x + 234 = 0
• x² - 39x - 6x + 234 = 0
• x(x - 39) - 6(x - 39) = 0
• (x - 39) - (x - 6) = 0
• x = 39 or x = 6

∴ x = 39 since 6 is small number (age)

Hence, the present age of father is 39 years and the present age of the son is (45 - x) = (45 - 39) = 6 years.