the sum of the ages of a father and his son is 54 years 2 years ago the product of their age is 400 find their present ages
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let father age be x and son age be 54-x
according to question
(x-2)(54-x-2)= 400
(x-2)(52-x)=400
52x -x2 -104 + 2x=400
x2- 54x +504=0
x = -b + sqroot of b2 -4ac/2a
+54+sqroot of 542 -4(1)(+504)
2
54 + sqroot of 2196-2016
2
54+ sqroot of 900
2
54 + 30
2
x=84/2, x=24/2
x=42 or 12
12 regected as father age cannot be 12
therefore father age= x= 42
son age=54-x= 54-42=12
according to question
(x-2)(54-x-2)= 400
(x-2)(52-x)=400
52x -x2 -104 + 2x=400
x2- 54x +504=0
x = -b + sqroot of b2 -4ac/2a
+54+sqroot of 542 -4(1)(+504)
2
54 + sqroot of 2196-2016
2
54+ sqroot of 900
2
54 + 30
2
x=84/2, x=24/2
x=42 or 12
12 regected as father age cannot be 12
therefore father age= x= 42
son age=54-x= 54-42=12
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