Question

The sum of the ages of a father and his son is 56 years. The ratio of their ages is 6:1. Find their present ages.​

Answer 1

Step-by-step explanation:

let the father's age be x and sons agebe y

so, x+y = 56

and x/y = 6/1

= x = 6y

so, 6y + y = 56

= 7y= 56

= y = 8 years

so x = 56-8 = 48 years

Answer 2

Answer:

Present age of father and his son is $48$ years and $8$ years respectively .

Step-by-step explanation:

To find : present age of father and his son .

Given : the sum of the ages of a father and his son is $56$ years. The ratio of their ages is $6:1$ .

Solution :

• As per given data we know that , the sum of the ages of a father and his son is $56$ years .The ratio of their ages is $6:1$ .
• Let , $6x$ and $1x$ be the age of father and son respectively .
• According to given condition we write as , $6x + 1x = 56$
• Using transposition method we find the value of $x$ , by transposing constants at RHS and leaving variables at LHS  .

        $6x + 1x = 56 \\7x = 56 \\ x =\frac{56}{7} \\x = 8$  

• Now , age of father = $6x = 6\times 8 = 48$ years

                  Age of son = $1x = 1\times 8 = 8$ years