Question

The sum of the ages of a father and his son is 72 years. After two years, father will be 4 years less than 3 times the age of his son. Then the present age of father is

Answer 1

Answer:

son is 18 and father is 54

Step-by-step explanation:

let the present age of son is x

and age of father is 72-x

then after 2 years

according to question

(72-x)+2 = 3(x+2)-4

72-x = 3x+6-4-2

72 - x = 3x+6-6

72-x = 3x

3x+x = 72

4x = 72

x = 72/4

x = 18

the present age of son is 18 years

the present age of father is 72-18 = 54

please mark brainliest !

Answer 2

Answer:

Write an equation for each statement

f = father's present age

s = son's

:

"The sum of ages of a father and his son is 72 years."

f + s = 72

:

" After 2 years .father will be 4 years less than 3 times the age of his son"

f + 2 = 3(s+2) - 4

f + 2 = 3s + 6 - 4

f + 2 = 3s + 2

f = 3s + 2 - 2

f = 3s

:

.find their present ages.

In the 1st equation replace f with 3s

3s + s = 72

s = 72/4

s = 18 is the son's age