Question

The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times

the father's age at that time. What is the present age of the father?​

Answer 1

Answer:

Let sons age = x years. Then fathers age = (45 - x)years.

(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9

Their ages are 36 years and 9 years.

MARK AS A BRAINLIEST PLZZZ

Answer 2

Answer:

their ages r 36, 9 years old.

Step-by-step explanation:

Let sons age = x years. Then fathers age = (45 - x)years.  

(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9  

Their ages are 36 years and 9 years.