Question

The sum of the ages of a man and his son is 45.five years ago, the product of their ages is equal to the 4 times of his father's age at that time. The ages of father and his son respectively are?

Answer 1

Answer:

Let the age of man be x and age of son be y.

So x+y=45

Five years ago,

x*y=4*(x-5)

On solving

age of father(x)=45-4.5=40.5 years

Age of son(y)=4.5 years

Step-by-step explanation:

Answer 2

Answer:

let the age of son be x

and the age of his father be y

x+y=45

(x-5)×(y-5)=4(x-5)

xy-5x-5y+25=4x-20

xy-5y=x-45

x=45-y from eq 1

(45-y)×y=y

45-y=1

y=44

x=1

age of son =1

age of father=44