Question

the sum of the ages of a man and his son is 52 years. eight years ago, the man was eight times as old as his son. find the present ages of the man and his son

Answer 1

let the son's age be=x
let the father's age be=8*x

x+8*x=52
x+x=52-8
2x=44
x=44/2
x=22

son's present age is 22
father's present age is 8*x=22*8=176
                                             

Answer 2

sum od age eight years ago = 52-16=36
age of son=36×1/9=4
age of man =36×8/9=32
present age of son =12
present ave of man =40