The sum of the ages of a son and father is 56 years. After four years, the age of the father will be three times that of the son. Their ages respectively are
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answer is age of son=12 years
age of father=44 years
present age of son=x
present age of father=y
eqn 1 is x+y=56
after 4 yrs the age of father =y+4
after 4 yrs the age of son =x+4
y+4=3(x+4)
y+4=3x+12
eqn 2 is 3x-y=-8
by solving eqn 1 & eqn 2
we get x=12 & y=44
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