The sum of the ages of a son and his father is 44 years and the product is 160,their ages are *
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sarithasaritha3592
29.08.2018
Math
Secondary School
+13 pts
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The sum of the ages of a father and son is 45 years. five years ago, the product of their ages was four times the fathers age at that time. the present age of father and son * 1 point
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abhi569
abhi569 Genius
Let the age of father be x years and age of his son be ( 45 - x ) years,
Five years ago,
Age of father = ( x - 5 ) years
Age of his son = ( 45 - x - 5 ) years = ( 40 - x ) years
According to the question,
Product of their ages five years ago = 4 × father's age five years ago
=> ( x - 5 ) ( 40 - x ) = 4( x - 5 )
= > \cancel{(x - 5)}(40 - x) = 4 \cancel{(x - 5)}
=> 40 - x = 4
=> 40 - 4 = x
=> 36 = x
Hence,
Present age of father = x years = 36 years
Present age of his son = ( 45 - x ) = ( 45 - 36 ) = 9 years