Question

The sum of the ages of father and his son before 3 years was 40 years. then after two years the sum of thier ages will become

Answer 1

Answer:

Son age = 6 years , father age = 45 years

Step-by-step explanation:

present age of son = x

age of son before 3 y = x - 3

sum of their ages before 3 y = 40

age of father before 3 y = 40 - x - 3

x - 3 + 40 + x -3 = 40

2x + 34 = 40

2x = 40 - 34

x = 6 ÷ 2

x = 3

present age of son = 3 years

age of son before 3 years = 0

age of father before 3 years = 40 - 0

= 40

age of son after 2 y = 3 + 2 years = 6 years

age of father after 2 y = 40 + 3 + 2 = 45 years

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