the sum of the ages of father and his son is 42 years. the product of the number the denoting in their ages is 185 find their ages.
Answers
Answer:
Let father’s age be x years
Son’s age = (42 – x) years
∴ The age of his son is (42 – x) years.
As per the given condition,
x (42 – x) = 185
∴ 42x – x2 = 185
∴ 0 = x2 – 42x + 185
∴ x2 – 42x + 185 = 0
∴ x2 – 5x – 37x + 185 = 0
∴ x (x – 5) – 37 (x – 5) = 0
∴ (x – 5) (x – 37) = 0
∴ x – 5 = 0 or x – 37 = 0
∴ x = 5 or x = 37
∵ 5 years cannot be the age of Father.
∴ It is unacceptable,
∴ x = 37
And 42 – x = 42 – 37 = 5
The father’s age is 37 years and son’s age 5 years.
Let father’s age be x years
Son’s age = (42 – x) years
∴ The age of his son is (42 – x) years.
As per the given condition,
x (42 – x) = 185
∴ 42x – x2 = 185
∴ 0 = x2 – 42x + 185
∴ x2 – 42x + 185 = 0
∴ x2 – 5x – 37x + 185 = 0
∴ x (x – 5) – 37 (x – 5) = 0
∴ (x – 5) (x – 37) = 0
∴ x – 5 = 0 or x – 37 = 0
∴ x = 5 or x = 37
∵ 5 years cannot be the age of Father.
∴ It is unacceptable,
∴ x = 37
And 42 – x = 42 – 37 = 5