Question

The sum of the ages of father and his son is 45 years. 5 years ago the product of their ages in year was 124 find their present age

Answer 1

Answer:

36 years and 9 years

Step-by-step explanation:

Let the present age of father be = x years

and that of son be = (45-x) years

Five years ago,

Father's age was = (x-5) years

Son's age was = (45-x-5) years = (40-x) years

ATQ,

(x-5)(40-x) = 124

40x - x² - 200 + 5x = 124

45x - x² = 324

x² - 45x + 324 = 0

x² - 9x - 36x + 324 = 0

x (x-9) - 36 (x-9) = 0

(x - 9)(x - 36) = 0

Since father's age is always more than the son's age the father's present age is 36 years and son's present age is 9 years.

Hope it helps you...

Answer 2

Answer:

Let,

Age of son =x

Father age=y

Sum of their ages=45

5 years ago product of their ages=124

Then,

Sum of their age before 5 years=35

Then,

Father present age=36years

Son's present age=9 years

Step-by-step explanation: