Question

The sum of the ages of father and his son is 45 years .5 years ago the product of their ages was 124 determine their present age

Answer 1

see above for the answer. if you like then comment me

Answer 2

Answer:

Step-by-step explanation:

Given :-

The sum of the ages of father and his son is 45 years .

5 years ago the product of their ages was 124.

To Find :-

Their Present Ages.

Solution :-

Let the present age of father be x years

And the present age of son be y years .

According to Question,

x + y = 45  ...(1)

Five years ago, the product of their ages was 124.

(x – 5) × (y – 5) = 124

⇒ (45 – y - 5) ×(y – 5) = 124  

⇒ 40y – y² - 200 + 5y = 124  

⇒ y²  - 45y  + 324 = 0  

⇒ y²  - 36y  - 9y + 324 = 0

⇒ y (y - 36) - 9 (y - 36) = 0

⇒ (y - 36) (y - 9) = 0

⇒ y = 36 or y = 9

Putting y value in Eq (i),

x + y = 45

x + 9 = 45

x = 45 - 9

x = 36

The present age of father = 36 years

The present age of son = 9 years.

Hence, the present age of father be 36 years and The present age of son is 9 years.