The sum of the ages of father and his son is 45 years .5 years ago the product of their ages was 124 determine their present age
Answers
Answer:
Step-by-step explanation:
Given :-
The sum of the ages of father and his son is 45 years .
5 years ago the product of their ages was 124.
To Find :-
Their Present Ages.
Solution :-
Let the present age of father be x years
And the present age of son be y years .
According to Question,
x + y = 45 ...(1)
Five years ago, the product of their ages was 124.
(x – 5) × (y – 5) = 124
⇒ (45 – y - 5) ×(y – 5) = 124
⇒ 40y – y² - 200 + 5y = 124
⇒ y² - 45y + 324 = 0
⇒ y² - 36y - 9y + 324 = 0
⇒ y (y - 36) - 9 (y - 36) = 0
⇒ (y - 36) (y - 9) = 0
⇒ y = 36 or y = 9
Putting y value in Eq (i),
x + y = 45
x + 9 = 45
x = 45 - 9
x = 36
The present age of father = 36 years
The present age of son = 9 years.
Hence, the present age of father be 36 years and The present age of son is 9 years.