The sum of the ages of five children born at the intervals of 3 years each, is 50 years. What is the age of the youngest child?
Answers
Answered by
0
let the age of the youngest child be x, then
the second child's age= x+3
the third child's age= x+3+3
the fourth child's age= x+3+3+3
the fifth child's age= x+3+3+3+3
A/Q
x+(x+3)+(x+3+3)+(x+3+3+3)+(x+3+3+3+3)=50
5x+30=50
5x=50-30
5x=20
x=4
age of the youngest child = 4years ANS
the second child's age= x+3
the third child's age= x+3+3
the fourth child's age= x+3+3+3
the fifth child's age= x+3+3+3+3
A/Q
x+(x+3)+(x+3+3)+(x+3+3+3)+(x+3+3+3+3)=50
5x+30=50
5x=50-30
5x=20
x=4
age of the youngest child = 4years ANS
Answered by
13
Answer:
Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.
According to Question now,
➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
➳ 5x + 30 = 50
➳ 5x = 50 - 30
➳ x = 20/5
➳ x = 4 years
Therefore,the age of youngest child is 4 years.
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