The sum of the ages of husband and wife at present is 100. Ten years ago the ratio of their ages was 9:7. What is the age of the husband?
A) 45 years B) 55 years C) 65 years D) 40 years
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Answer:
let the age of husband = x
let the age of wife = y
x + y = 100 ------- (1)
(x-10) / (y -10) = 9/7
7x-70 = 9y-90
7x - 9y = -90+70
7x - 9y = -20 --------- (2)
x + y = 100 * 7
7x-9y = -20 * 1
7x+7y= 700
7x-9y= -20
(-) (+) (+)
16y= 720
y = 720 / 16
y = 45
NOW BY ELIMINATION METHOD WE GET VALUE OF X
Let take the eq. 1
x + y = 100
x+ 45= 100
x= 100-45
x= 55
NOW WE GET THE VALUE OF X= 55 YEARS
HOPE THIS HELP U
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