The sum of the ages of husband and wife at present is 60. Four years ago the ratio of their ages was 7:6. What is the age of the husband?
A) 28 years B) 32 years C) 42 years D) 38 years
Answers
Answered by
6
Answer :
B) 32 years
is a right option
Answered by
116
Sᴏʟᴜᴛɪᴏɴ :-
Let us Assume that, Present age of Husband is x years.
Than,
→ Present age of wife = (60 - x) years.
So,
→ 4 years ago, husband was = (x - 4) years old.
→ 4 years ago, wife was = (60 - x) - 4 = (56 - x) years old.
A/q,
→ (x - 4) : (56 - x) = 7 : 6
→ (x - 4) / (56 - x) = 7/6
→ 6(x - 4) = 7(56 - x)
→ 6x - 24 = 7*56 - 7x
→ 6x + 7x = 7*56 + 24
→ 13x = 392 + 24
→ 13x = 416
→ x = 32 years. (B) (Ans.)
Hence, Present age of Father is 32 Years.
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