Question

the sum of the ages of presents brother is 13 and the different between there agers is 3 find there ages​

Answer 1

Answer:

Perimeter of trapezium = 104 m

Length of Non-parallel sides = 18 m and 22 m

Altitude = 16m

Area of Trapezium = 0.5 * (sum of parallel sides)*altitude ------ (1)

Sum of parallel sides = Perimeter - (sum of non-parallel sides) = 104 m - (18+22)m = 104-40 m = 64 m

From (1), Area of Trapezium = 0.5*64*16 = 512 m^2

Ans: Area of trapezium = 512 m^2

Answer 2

Answer:

let their ages be x and y

x+y=13

x-y=3

x+y+x-y=13+3

2x=16

x=8

x+y=13

8+y=13

y=13-8

y=5