the sum of the ages of sanjay and vijay is thrice the sum of their ages 5 yrs ago. what is the product of their present age, if the sum of the squares of thir ages 5 yrs ago was 100?
Answers
Answer:
12.5 years
Step-by-step explanation:
as attached with this solution
The sum of the ages of Sanjay and Vijay is thrice the sum of their ages 5 yrs ago
Let the present age of Sanjay be x
Present age of Vijay be y
Five years ago ,
Age of Sanjay = x - 5
Age of Vijay = y - 5
➠ x + y = = 3 [ (x - 5) + (y - 5) ]
➠ x + y = 3 [ x - 5 + y - 5 ]
➠ x + y = 3 [ x + y - 10 ]
➠ x + y = 3x + 3y - 30
➠ 3x + 3y - x - y = 30
➠ 2x + 2y = 30
➠ x + y = 15 ... (1)
The sum of the squares of their ages 5 yrs ago was 100
➳ ( x - 5 )² + ( y - 5 )² = 100
➳ x² + 25 - 10x + y² + 25 - 10y = 100
➳ x² + y² - 10x - 10y + 50 = 100
➳ x² + y² - 10x - 10y = 100 - 50
➳ x² + y² - 10 ( x + y ) = 50
➳ x² + y² - 10 ( 15 ) = 50 [ From (1) ]
➳ x² + y² - 150 = 50
➳ x² + y² = 200
- ( a + b )² = a² + b² + 2ab
⇒ a² + b² = ( a + b )² - 2ab
➳ ( x + y )² - 2xy = 200
➳ ( 15 )² - 2xy = 200 [ From (1) ]
➳ 225 - 200 = 2xy
➳ 2xy = 25
➳ xy = 25/2
➳ xy = 12.5 years
Product of their present ages is 12.5 years