Question

the sum of the ages of Seeta and Geeta is 29 years Sita is three years younger than Geeta find their present ages

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Answer 1

Present age of Seeta = 13 years

Present age of Geeta = 16 years

Step-by-step explanation:

Let,

• Present age of Seeta = x
• Present age of Geeta = x + 3

The sum of the ages of Seeta and Geeta is 29 years.

★ According to the Question :

⇒ x + (x + 3) = 29

⇒ 2x + 3 = 29

⇒ 2x = 29 - 3

⇒ 2x = 26

⇒ x = 26/2

⇒ x = 13

Present age of Seeta = 13 years

• Present age of Geeta = x + 3

⇒ x + 3

⇒ 13 + 3

⇒ 16

Present age of Geeta = 16 years

Therefore,

Present age of Seeta = 13 years

Present age of Geeta = 16 years

Answer 2

Answer:

• Present age of Seeta = 13 years
• Present age of Geeta = 16 years

Explanation:

Given information,

The sum of the ages of Seeta and Geeta is 29 years. Seeta is three years younger than Geeta. Find their present ages.

• Sum of ages of Seeta and Geeta = 29 years
• Seeta is younger than Geeta by = 3 years

Let,

• Present age of Geeta = y years
• As it is stated in question that Seeta is three years younger than Geeta. So, Present age of Seeta = (y - 3) years

According to the Question,

• Sum of ages of Seeta and Geeta = 29 years

Therefore,

➻ y + (y - 3) = 29

➻ y + y - 3 = 29

➻ 2y - 3 = 29

➻ 2y = 29 + 3

➻ 2y = 32

➻ y = 32/2

➻ y = 16

• Henceforth, present age of Geeta is 16 years.

Now,

➻ Present age of Seeta = (y - 3) years

Putting value of y,

➻ Present age of Seeta = (16 - 3) years

➻ Present age of Seeta = (13) years

➻ Present age of Seeta = 13 years

• Henceforth, present age of Seeta is 13 years.

Verification,

• Sum of ages of Seeta and Geeta = 29 years

Therefore,

➻ y + (y - 3) = 29

Putting value of y,

➻ 16 + (16 - 3) = 29

➻ 16 + (13) = 29

➻ 16 + 13 = 29

➻ 29 = 29

➻ LHS = RHS

Hence, Verified ✔

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