Math, asked by shwetachaurasiya51, 2 days ago

the sum of the ages of Seeta and Geeta is 29 years Sita is three years younger than Geeta find their present ages Give write answer.. don't spam.​ and answer my all questions please ​

Answers

Answered by vachigupta3007
1

Step-by-step explanation:

let Seeta`s age be = x

let Geeta age be = y

so

x + y = 29

y = 29 - x

also that

y - x = 3

so we can write

y - x = 3

( 29 - x ) - x = 3

29 - 2x = 3

29 = 3 + 2x

29 - 3 = 3x

26 = 3x

26 / 3 = x

8.66 = x

Answered by Limafahar
6

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Let,

  • present age of Seeta = x
  • present age of Geeta = x + 3

Given,

  • the sum of the ages of Seeta and Geeta is 29 years

x + ( x + 3 ) = 29

→ 2x + 3 = 29

→ 2x = 29 - 3

→ 2x = 26

→ x = 26/2

x = 13

-› present age of seeta = x = 13

present age of Geeta,

x + 3

→ 13 + 3

16

-› present age of Geeta = x + 3 = 16

Therefore,

  • present age of seeta = x = 13
  • present age of Geeta = x + 3 = 16
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