The sum of the ages of the father and his two children is 55 years hence, the ratio of father's age to the sum of the ages of his two children is 9:5. Find the father's present age. CBSE Class 10 Chp. Linear equations in two variables NOT APPLICABLE, IDIOTIC AND SPAM ANSWERS WILL BE REPORTED IMMEDIATELY Please answer urgently!!
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Answer : Let the age of the sons be x and y.
Given that Father’s age is three times the age of his two sons.
Therefore, present age of father is 3(x+y)
Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.
Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.
3(x+y)+5 = 2(x+5+y+5)
3x+3y+5 = 2x+10+2y+10
3x+3y+5 = 2x+2y+20
3x-2x+3y-2y = 20–5
x+y = 15
Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)
Thus the age of the father is 45.
Hope it helps you
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