The sum of the ages of three children born at the intervals of 3 years each, is 39 Years.
What is the age of the youngest child?
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Answer:
let the ages be x
then
x
x+3
x+3+3
now x+x+3+x+6=39
=3x+9=39
=3x=39-9
=3x=30
=x=30/3
=x=10 years
ages =x= 10 years
=x+3=10+3=13
=x+6=10+6=16
hence the age of the youngest child is 10 years
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