the sum of the ages of three person is 150 years. 10 years ago their ages were in the ratio 7:8:9. find their present ages
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Let 10 years ago there ages were 7x,8x,9x
So there current ages are 7x+10,8x+10,9x+10
Sum of their ages=150
7x+10+8x+10+9x+10=150
24x=150-30
24x=120
x=5
So present ages are 45,50,55
So there current ages are 7x+10,8x+10,9x+10
Sum of their ages=150
7x+10+8x+10+9x+10=150
24x=150-30
24x=120
x=5
So present ages are 45,50,55
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