The sum of the ages of two brothers is 24. In three years time, the elder brother will be twice as old as the younger brother. what us the present age of brothers?
Answers
Answer:
the sum of ages of 2 brothers=24
age of elder bro= is x
age of younger brother = y
after three years
age of elder bro = x+3
age of youngerbrother = y+3 (x+y=24)year
elder brother twice = x+3×2
x+6
younger brother age =y+3
the present age of elder bro = x+6
the present age of younger brother = y+3
Explanation:
may It help u
• Sum of ages of two brothers = 24
• After 3 years ago elder brother will be twice as old as younger brother.
• What are the present Ages of both brothers?
Let the age of elder brother and age of younger brother be x and y years.
Given that,
Sum of ages of two brothers is 24.
Therefore,
x + y = 24........ eq(1)
Again, it’s given that
After 3 years ago elder brother will be twice as old as younger brother.
After 3 years,
Age of younger brother = y + 3
Age of elder brother = 2 ( y + 3)
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According to the question :-
⟼ x+3=2(y+3)
⟼ x+3=2y+6
⟼ x−2y=3.........eq(2)
From eq(1), we get
⟼ x = 24 - y
Now, put x = 24 - y in eq(2)
⟼ x−2y=3
⟼ 24 - y - 2y = 3
⟼ 24 - 3y = 3
⟼ -3y = 3 - 24
⟼ -3y = -21
⟼ y = 7
Substituting the value of y in eq(1), we get
⟼ x = 24 - y
⟼ x = 17
Hence,
Present age of elder brother is = 17 years
Present age of younger brother is = 7 years