Question

.
The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in
years was 48. Is the above situation possible? If so, determine their present ages.​

Answer 1

Answer:

b^2-4ac<0

the equation doesn't have real roots

the situation is not possible

Answer 2

answer-

it's not possible.

explanation-

let one's age be 'x'

let the other person's age be 'y'

from condition one-

x+y=20 ---1

from condition two-

(x-4)×(y-4)=48 ---2

from equation 1

x=20-y

substituting value in equation 2

(20-y-4)×(y-4)=48

=> (16-y)×(y-4)=48

=>16y-68-y²+4y=48

=>-y²+20y-68=48

=>-y²+20y=48+68

=>-y²+20y=116

=>-y+20y=√116

=>19y=√116

=>y=√116÷19

(I don't think we can substitute this value in equation to get a correct answer)

(therefore, not possible)