Math, asked by praneetgopnarayan2, 8 months ago

The sum of the ages of two friends is 22 years. Four years ago, the product of

their ages in years was 48.Find their present ages.

Answers

Answered by krishna02299

Let,

Let,Age Of 1st Friend = x Years

Age of 2nd Friend = 22-x

Four years ago age Of 1st Friend = x-4

Four years Ago Age Of 2nd Friend = 22-x-4

= 18-x

• According to Question

(x - 4)(18 - x) = 48

18x - x² - 72 + 4x = 48

-x² + 22x - 72 = 48

x² - 22x + 72 = - 48

x² - 22x + 72 + 48 = 0

x² - 22x + 120 = 0

By Middle Term Splitting

x² - (10 + 12)x +120 = 0

x² - 10x - 12x + 120 = 0

[x( x - 10) - 12( x -10) = 0

(x -12) ( x - 10 ) = 0

so,

(x-12) = 0

x = 12

Age Of 1st Friend = 12 Years

Age Of 22nd Friend = 22-12

. . . = 10 Years

Again,

( x-10) = 0

x = 10

Age Of 1st Friend = 10 Years

Age Of 2nd Friend = 22 - 10

. . . = 12 Years

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