the sum of the agesof A and B is 60 years. 10 years ago. If A was thrice as old as B , find their present ages.
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Let the present age of A and B be x and y respectively.
Given,x+y=60
Also,
(x-10)=3(y-10)
x-10=3y-30
x=3y-20
Substitute this value in the first equation,
then,
3y-20+y=60
4y=80
Therefore, y=20.
x=40
That is, the present ages are 40 and 20.
Hope it helps.
Please mark it as brainliest.
Given,x+y=60
Also,
(x-10)=3(y-10)
x-10=3y-30
x=3y-20
Substitute this value in the first equation,
then,
3y-20+y=60
4y=80
Therefore, y=20.
x=40
That is, the present ages are 40 and 20.
Hope it helps.
Please mark it as brainliest.
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