History, asked by Questionable, 1 year ago

The sum of the angle measures of any triangle is 180°. Find the angle measures of a triangle if the second angle measures 10° less than twice the first, and the third angle measures 25° more than the second.


Questionable: It's supposed to be MATH. Sorry about that. :)

Answers

Answered by shivnarayan85
8

Answer:

First angle =35 degrees

Second angle=60 degrees

Third angle =85 degrees

Explanation:

Let the first angle be x.

Second angle is 2x-10.

Third angle is (2x-10)+25.

The sum of angles in a triangle is 180.

x+2x-10+2x-10+25=180

5x+5=180

5(x+1)=180

x+1=36

X=35


Questionable: Thank you very much for the help!
Answered by MяƖиνιѕιвʟє
164

\bf{\red{\underline{\bf{Given}}}}

The sum of the angle measures of any triangle is 180°. Find the angle measures of a triangle if the second angle measures 10° less than twice the first, and the third angle measures 25° more than the second.

\bf{\red{\underline{\bf{ToFind}}}}

  • Angles of triangle

\bf{\red{\underline{\bf{Solution}}}}

Let the first angle be x °

Then,

Second angle = ( 2x - 10)°

Third angle = (2x - 10) + 25 = (2x + 15)

Now,

We know that,

  • Sum of angles of triangle = 180°

So,

x + (2x - 10) + (2x + 15) = 180

5x + 5 = 180

5x = 180 - 5

x = 175/5

x = 35

Therefore,

First angle = x = 35°

Second angle = (2x - 10) = 2×35 - 10 = 70-10 = 60°

Third angle = (2x + 15) = 2×35 + 15 = 70 + 15 = 85°

Similar questions