Math, asked by SanathJayaprakash, 16 hours ago

The sum of the angles of a polygon is 8100°. How many sides does it have?​

Answers

Answered by Anonymous
24

Sum of the angles = 8100°

Sum of the angles of n-sided polygon = (n – 2) × 180°

⇒ 8100° = (n – 2) × 180°

⇒8100/180 = n - 2

⇒ 45 = n – 2

⇒ n = 45 + 2

⇒ n = 47

∴ The number of sides of polygon having sum of the angles of 8100° is 47 sides.

Answered by rehanna0911
5

Answer:

Sum of the angles = 8100°

Sum of the angles of n-sided polygon = (n – 2) × 180°

⇒ 8100° = (n – 2) × 180°

⇒ n – 2 = 45

⇒ n = 45 + 2

n = 47

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