the sum of the ap 2,7,12....to 10 terms
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t1=a=2,t2=7 ,t3= 12, t10=?,n=10
d=t2-t1=7-2=5
d= t3- t2=12-7= 5
given sequence of an A.P.
tn=a+(n-1)d
t10= 2+(10-1)×5
t10=2+9×5
t10=2+45
t10=47
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