Question

the sum of the AP 34,32,30,...,10 is:

Answer 1

s=(2a+(n-1)d)n/2=n(a+l)/2
)
(10=a+(n-1)d)
10=34+(n-1)-2
12=n-1
n=13

s={13(34+10)}/2
=572/2
=286

Answer 2

a=34
d=2
l=10
n terms=a+(n-1)d=l
=34+(n-1)2=10
=34+2n-2=10
=2n+32=10
=2n=10-32
=2n=-22
=n=-11
It means 11
Sum=n/2(a+l)
=11/2×44
=242
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